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Stuck with Jeni's Logic...Help me out..!!
- From: "Sachidanandam E K" <sachidanandam dot kumaraswamy at kla-tencor dot com>
- To: <xsl-list at lists dot mulberrytech dot com>
- Date: Wed, 4 Apr 2001 15:13:18 +0530
- Subject: [xsl] Stuck with Jeni's Logic...Help me out..!!
- Reply-to: xsl-list at lists dot mulberrytech dot com
Hi Jeni and Hi all..
My need is to get a different of A (xml file) and B (xml File) and then
get C (as xml file).
I used the logic explained in the below link as jeni explained it.
http://sources.redhat.com/ml/xsl-list/2000-07/msg00320.html
Still not able to get a clear picture upon it.
When telling about XML files i can post it when anone wish to see it .
Let me have a reply upon this.
Sample XML is below:
A.xml.
-------
<RecipeVersions>
<RecipeVersion>
<VersionID>{007A6506-B4E1-4F2C-B4CD-A725B41DDA33}</VersionID>
<BodySize>100</BodySize>
<Identifier>Anoop>/RBClass1/Test111</Identifier>
<Version>1</Version>
</RecipeVersion>
<RecipeVersion>
<VersionID>{010EA2DE-1063-47B8-82FF-4D15EA0BCA2A}</VersionID>
<BodySize>100</BodySize><Identifier>Anoop>/RBClass1/Test198</Identifier>
<Version>1</Version></RecipeVersion>
<RecipeVersion><VersionID>{1ED0B241-862C-4803-98BF-8E1385A38AAE}</VersionID>
<BodySize>100</BodySize><Identifier>Anoop>/RBClass1/Test134</Identifier><
Version>1</Version></RecipeVersion>
</RecipeVersions>
In the similar way b.xml will be there. Based on VersionID I need to
compare A wish B and put into C elements of A which is not found in B.xml.
Hoping to get a reply.
Thanks in advance
Sachi..
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